The FileCopy statement in VBA (Visual Basic for Applications) is used to copy a file from one location to another. It’s a straightforward and efficient way to duplicate files in your file system. Here’s how to use the FileCopy statement:
FileCopy SourceFilePath, DestinationFilePath
SourceFilePath: The path of the file you want to copy. This should include the full path and the name of the file.
DestinationFilePath: The path where you want the new file to be placed, including the new file name.
Important Points to Consider
File Overwriting: If a file with the same name already exists in the destination location, it will be overwritten without warning. To prevent unintentional data loss, you might want to check if the destination file already exists before performing the copy operation.
Error Handling: FileCopy can fail for various reasons (like if the source file does not exist or the destination path is invalid). It’s good practice to include error handling in your code.
File Paths: Both the source and destination paths need to be fully qualified (i.e., they should include the complete path and file name).
Here’s a simple example demonstrating the use of FileCopy:
Dim sourcePath As String
Dim destinationPath As String
' Specify the source and destination paths
sourcePath = "C:\path\to\source\file.txt"
destinationPath = "C:\path\to\destination\newfile.txt"
' Optional: Check if the source file exists
If Dir(sourcePath) <> "" Then
' Copy the file
FileCopy sourcePath, destinationPath
MsgBox "File copied successfully!"
MsgBox "Source file does not exist."
In this example, the FileCopy statement is used to copy a file from sourcePath to destinationPath. Before copying, the code checks if the source file exists using the Dir function. This is a simple way to prevent runtime errors if the source file is missing.
You can add error handling to manage any issues that might arise during the file copy operation:
On Error GoTo ErrorHandler
' ... (rest of your code) ...
MsgBox "An error occurred: " & Err.Description
With this structure, if an error occurs during the execution of the CopyFileWithErrorHandling subroutine, the code execution will jump to the ErrorHandler section, and a message box will display the error description.